(y+5)(y-4)=y^2

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Solution for (y+5)(y-4)=y^2 equation:


Simplifying
(y + 5)(y + -4) = y2

Reorder the terms:
(5 + y)(y + -4) = y2

Reorder the terms:
(5 + y)(-4 + y) = y2

Multiply (5 + y) * (-4 + y)
(5(-4 + y) + y(-4 + y)) = y2
((-4 * 5 + y * 5) + y(-4 + y)) = y2
((-20 + 5y) + y(-4 + y)) = y2
(-20 + 5y + (-4 * y + y * y)) = y2
(-20 + 5y + (-4y + y2)) = y2

Combine like terms: 5y + -4y = 1y
(-20 + 1y + y2) = y2

Add '-1y2' to each side of the equation.
-20 + 1y + y2 + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-20 + 1y + 0 = y2 + -1y2
-20 + 1y = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-20 + 1y = 0

Solving
-20 + 1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 1y = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 1y = 0 + 20
1y = 0 + 20

Combine like terms: 0 + 20 = 20
1y = 20

Divide each side by '1'.
y = 20

Simplifying
y = 20

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